When the speed of a car is v, the minimum distance over which it can be stopped is s. If the speed becomes n v, what will be the minimum distance over which it can be stopped during same time

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s/n

n s

s/n2

n2s

answer is D.

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Detailed Solution

v2 =u2 + 2as or v2 -u2 = 2asMaximum retardation, a=v2/2sWhen the initial velocity is n v, then the distance overwhich it can be stopped is given bysn=u022a=(nv)22v2/2s=n2s

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