First slide

Rolling motion

Question

When a stick is released (as shown in figure), its free end velocity when its strikes the ground is :

Easy

A

4.2m/s
B

1.4 m/s
C

2.8 m/s
D

$\sqrt{6} m / s$

Solution

$\begin{array}{l} By COME, mgh = \frac{1}{2} {Iω}^{2} \Rightarrow mg (\frac{l}{2}) = \frac{1}{2} (\frac{{ml}^{2}}{3}) {(\frac{v}{l})}^{2} \\ \Rightarrow v = \sqrt{3 gl} = 4 .2 m / s \end{array}$

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