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Q.

When the string of a conical pendulum makes an angle of 45° with the vertical, its time period is T1. When the string makes an angle of 60° with the vertical, its time period is T2. Then T12/T22 is

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a

2

b

2

c

0.5

d

none of these

answer is C.

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Detailed Solution

In conical pendulum,     Tcos⁡θ=mg= constant ⇒T1cos⁡θ1=T2cos⁡θ2    T1T2=cos⁡θ2cos⁡θ1=cos⁡60∘cos⁡45∘                          =1/21/2=12T1T22=12
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