Q.
When the string of a conical pendulum makes an angle of 45° with the vertical, its time period is T1. When the string makes an angle of 60° with the vertical, its time period is T2. Then T12/T22 is
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a
2
b
2
c
0.5
d
none of these
answer is C.
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Detailed Solution
In conical pendulum, Tcosθ=mg= constant ⇒T1cosθ1=T2cosθ2 T1T2=cosθ2cosθ1=cos60∘cos45∘ =1/21/2=12T1T22=12
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