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Q.

When the string of a conical pendulum makes an angle of 45° with the vertical, its tension is T1.When the string makes an angle of 60° with the vertical, its tension is T2. Then T12/T22 is

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a

2

b

2

c

0.5

d

None of these

answer is D.

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Detailed Solution

In conical pendulum,T cosθ= mg = constant ⇒T1cosθ1= T2cosθ2T1T2=cosθ1cosθ2=cos60ocos45o⇒=1/21/2=12⇒T1T22=12
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When the string of a conical pendulum makes an angle of 45° with the vertical, its tension is T1.When the string makes an angle of 60° with the vertical, its tension is T2. Then T12/T22 is