When a string is divided into three segments of length l1, l2 and l3 the fundamental frequencies of these three segments are f1 , f2 and f3 respectively. The original fundamental frequency (f) of the string is
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a
1f = 1f1+1f2+1f3
b
f = f1+f2+f3
c
f = f1+f2 + f3
d
1f = 1f1+1f2+1f3
answer is D.
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Detailed Solution
Fundamental frequency f = v2lf1 = v2l1; f2 = v2l2 and f3 = v2l3⇒1f= 1f1+1f2+1f3