First slide

Ohm's law

Question

When the switch is closed, then initial current through 1 $Ω$ resistor is (see figure)

Easy

A

12 A
B

4 A
C

10/7 A
D

3 A

Solution

Initially cement through the capacitor will be maximum
So 6 $Ω$ and 3 $Ω$ are in parallel total resistance
$\begin{array}{l} \frac{6 \times 3}{9} + 1 = 3 Ω \\ i = \frac{12}{3} = 4 Ω \end{array}$

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