When a system is taken from state i to state/along the path iaf, it is found that Q = 50 cal and W = 20 cal. Along the path ibf, Q = 36 cal. W along the path ibf is:
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a
14 cal
b
6 cal
c
16 cal
d
66 cal
answer is B.
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Detailed Solution
∆U=Q-W=50-20=30 cal Along path ibf, W=Q-∆U =36-30=6 cal