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When the temperature of a rod increases from t to $t + Δt$ , its moment of inertia increases from I to $I + ΔI$ . If be the coefficient of linear expansion of the rod, then the value of $\frac{ΔI}{I}$ is

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2αΔt

αΔt

αΔt2

Δtα

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detailed solution

Correct option is A

I∝R2ΔTI=2ΔRR=2αΔt

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When the temperature of a rod increases from t to t+Δt , its moment of inertia increases from I to I+ΔI . If be the coefficient of linear expansion of the rod, then the value of ΔII is

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When the temperature of a rod increases from t to $t + Δt$ , its moment of inertia increases from I to $I + ΔI$ . If be the coefficient of linear expansion of the rod, then the value of $\frac{ΔI}{I}$ is