When the tension in a metal wire is T1, its length is l1. When the tension is T2, its length is l2.The natural length of wire is
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a
T2T1l1+l2
b
T1l1+T2l2
c
l1T2−l2T1T2−T1
d
l1T2+l2T1T2+T1
answer is C.
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Detailed Solution
Y=FlaΔlY, I and a are constants∴ FlΔl= constant or Δl∝F Now, l1−l=T1 and l2−l=T2 Dividing, l1−ll2−l=T1T2or l1T2−lT2=l2T1−lT1 or lT1−T2=l2T1−l1T2or l=l2T1−l1T2T1−T2 or l=l1T2−l2T1T2−T1