Q.

When the tension in a string is increased by 44%. The frequency increased by 5 Hz the frequency of the string is

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a

100 Hz

b

200 Hz

c

150 Hz

d

25 Hz

answer is D.

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Detailed Solution

Tension T1=100 Tension T2=144 Frequency n2=n1+5 Frequency n1=? n1n2=T1T2 n1n1+5=100144 n1n1+5=1012 12n1=10n1+50 2n1=50  ∴ n1=25 Hz
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