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Q.

When a thin transparent plate of Refractive Index 1.5  is introduced in one of the interfering beam produces 10  fringes shift. If it is replaced by another thin plate of half the thickness and of R.I. 1.7  the number of fringes that undergo displacement is

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a

23

b

14

c

28

d

7

answer is D.

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Detailed Solution

Refractive index μ1=1.5 Number of fringes n1=10 Thickness t1=t Refractive index μ2=1.7 Thickness t2=t2 Number of fringes n2=?  n1n2=(μ1−1)t1(μ2−1)t2       (  ∵nλ=(μ−1)t  ) 10n2=(1.5−1)t(1.7−1)t2 10n2=57×2 ∴  n2=7
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