First slide

Beats

Question

When a tuning fork of frequency 341 is sounded with another tuning fork, six beats per second are heard. When the second tuning fork is loaded with wax and sounded with the first tuning fork, the number of beats is two per second. The natural frequency of the second tuning fork is

Moderate

A

334
B

339
C

343
D

347

Solution

n_A = Known frequency = 341 Hz, n_B = ?
x = 6 bps, which is decreasing (i.e. x $↓$ ) after loading (from 6 to 1 bps)
Unknown tuning fork is loaded so n_B $↓$
Hence n_A – n_B $↓$ = x $↓$ ... (i) $\to$ Wrong
n_B $↓$ – n_A = x $↓$ ... (ii) $\to$ Correct
$\Rightarrow$ n_B = n_A + x = 341 + 6 = 347 Hz.

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App