Q.

When a tuning fork A of unknown frequency is sounded with another tuning fork B of frequency 256 Hz, then 3 beats per second are observed. After that A is loaded with wax and sounded, the again 3 beats per second are observed. The frequency of the tuning fork A is

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*
An Intiative by Sri Chaitanya

a

250 Hz

b

253 Hz

c

259 Hz

d

262 Hz

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

It is given that nA = Unknown frequency = ?nB = Known frequency = 256 Hzx = 3 bps, which remains same after loading Unknown tuning fork A is loaded so nA↓Hence nA↓ – nB  = x        ... (i)        →       Correct            nB  – nA↓ = x        ... (ii)       →        Wrong⇒ nA = nB + x = 256 + 3 = 259 Hz.
Watch 3-min video & get full concept clarity
score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon