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Q.

When two bodies approach each other with the different speeds, the distance between them decreases by 120 m for every one minute. If they are moving in same direction, the distance between them increases by 90 m for very one minute. The speeds of the bodies are

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a

2 ms–1 and 0.5 ms–1

b

3 ms–1  and 2 ms-1

c

1.75 ms–1 and 0.25 ms–1

d

2.5 ms–1 and 0.5 ms–1

answer is C.

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Detailed Solution

The relative velocity is vector subtractionV1+V2 = 120/60 = 2 ; V1 - V2 = 90/60 = 1.5∴2V1 = 3.5 ⇒ V1 = 3.5/2V1 = 1.75 ms-1 ; Hence V2 = 0.25 ms-1
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When two bodies approach each other with the different speeds, the distance between them decreases by 120 m for every one minute. If they are moving in same direction, the distance between them increases by 90 m for very one minute. The speeds of the bodies are