Download the app

Questions  

When two capacitors one of 3 μF and the other of 6 μF arc connected in series and the combination is charged to a potential difference of 120 volt, the potential difference across 3 μF capacitor is

a
40 V
b
60 V
c
80 V
d
180 V

detailed solution

Correct option is C

V1+V2=120 volt and V1V2=C2C1=2 ∴ V1=2V2Now 2V3+V2=120    or    V2=40 volt and   V1=2×40=80 volt.

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

ln the circuit shown in figure the potential difference across the 4.5 μF capacitor is


phone icon
whats app icon