When two displacements represented by y1=a sin ωt and y2 =b cos ωt are superimposed the motion is :
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a
simple harmonic with amplitude ab
b
simple harmonic with amplitude a2+b2
c
simple harmonic with amplitude a+b2
d
not a simple harmonic
answer is B.
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Detailed Solution
y1=a sin ωt and y2= b cos ωt =-b sin ωt+π2Since the frequencies for both SHMs are same, resultant motion will be SHM. NowAmplitude A=A12+A22+2A1A2 cos θ Here A1=a,A2=b and ϕ=π2So A=a2+b2 Aa2+b2