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Q.

When two identical bar magnets placed one above the other, such that they are mutually perpendicular and bisect each other. The time period of oscillation in a horizontal magnetic field is 4 seconds. If one of the magnets is removed the time period of the other in the same field (21/4=1.189)

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a

1.34sec

b

2.34sec

c

3.36sec

d

4.34sec

answer is C.

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Detailed Solution

T=2π1MBH and T1T2=l1I2×M2M1=2/I×M2M=21/4

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When two identical bar magnets placed one above the other, such that they are mutually perpendicular and bisect each other. The time period of oscillation in a horizontal magnetic field is 4 seconds. If one of the magnets is removed the time period of the other in the same field (21/4=1.189)