Q.
When two resistances are connected in parallel then the equivalent resistance is 6/5Ω. When one of the resistance is removed then the effective resistance is 2Ω . The resistance of the wire removed will be
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a
3 ohm
b
2 ohm
c
35ohm
d
65ohm
answer is A.
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Detailed Solution
R1R2R1+R2=65 If R2 is removed R1 =2Ω2R22+R2=65⇒5R2=6+3R2⇒R2=3Ω
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