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Q.

When two resistors of 100±2% ohm and 300±1% ohm are connected in series. Value of equivalent resistance is

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a

400±5 ohm

b

400±2% ohm

c

400±3 ohm

d

400±8% ohm

answer is A.

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Detailed Solution

R=R1+R2=100+300=400∆R=∆R1+∆R2 Here ∆R1=2100×100=2and ∆R2=1100×300=3R=400±5 Ω
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