When unit mass of water boils to become steam at 100°C, it absorbs Q amount of heat. The densities of water and steam at 100°C are ρ1 & ρ2 respectively and the atmospheric pressure is ρ0 . The increase in the internal energy of water is _________

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Zero

Q+ ρ0[1ρ1−1ρ2]

Q+ ρ0[1ρ2−1ρ1]

Q− ρ0[1ρ1+1ρ2]

answer is B.

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Detailed Solution

dQ=dU + dW= dU +PdVdW=P0V2−V1=P0mρ2−mρ1=P0×11ρ2−1ρ1 ∴dU=Q−P0×11ρ2−1ρ1=Q+P01ρ1−1ρ2

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