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Q.

When 100V dc is applied across a solenoid, a current of 1.0A flows in it. When 100V ac is applied across the same coil. The current drops to0.5A. if the frequency of the ac source is 50Hz the impedance and inductance of the solenoid are

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a

200Ω and 0.55H

b

100Ω and 0.86H

c

200Ω and 1.0H

d

100Ω and 0.93H

answer is A.

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Detailed Solution

In case of d.c, ω=0 and hence Z=R ∴Z=R=EI=1001=100Ω For AC:Z=[R2+(2πnL)2]1/2 Or 200=[(100)2+(100πL)2]1/2(∵Z=1000.5=200Ω) Solving, we get L=0.55H.
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