When a viscous liquid is flowing through a horizontal capillary tube. The flow is laminar, difference in pressure between the ends of the pipe is Δp and the discharge is found to be Q. When two such identical tubes are connected in series , what should be the difference in pressure between its ends if the discharge through it is 2Q?
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a
8 ΔP
b
ΔP
c
2 ΔP
d
4 ΔP
answer is D.
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Detailed Solution
By poiseulle's equation Q=π.Δp.r48ηl and 2Q=π.Δp1.r48η2l∴ 2QQ=ΔP12.ΔP⇒ΔP1=4ΔP