When water is boiled under a pressure of 2 atm, the heat of vaporization is 2.20×106Jkg−1 and the boiling point is 120°C. At this pressure, 1 kg of water has a volume of 10-3 m3 and 1 kg of steam has a volume of 0.824 m3. What is the work done when 1 kg of steam is formed at this temperature?

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answer is 166.74.

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Detailed Solution

Work done =p(ΔV) (at constant pressure) ∴ W =2atm×(0.824−0.001)m3⇒ W =2×1.013×105Nm−2×0.823m3 =166.74kJ

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