When young's double slit experiment is conducted in vacuum, number of fringes observed on a given length of the screen is 81. When the whole set up is immersed in water, number of fringes observed on the same length of the screen will be (Refractive index of water = 4/3)
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a
84
b
108
c
96
d
112
answer is B.
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Detailed Solution
Fringe width β=λ0dSo number fringes formed on a length L of the screen, N=LβWhen the whole set up is immersed in water fringe width β1=(λ/μ)Δd=βμ∴ Number of fringes, N1=Lβ1=Lβ/μ=μN⇒N1=43×81=108