Which of the following expression does not represent SHM?

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A cos ωt

A sin 2 ωt

A sin ωt + B cos ωt

A sin2 ωt

answer is D.

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Detailed Solution

For SHM, d2ydt2 ∝ -yIf y = A sin2 ωt dydt = (2A sin ωt cos ωt)ω = = Aω sin 2 ωtd2ydt2 = +2 Aω2cos 2 ωti.e., d2ydt2 is not proportional to -y

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