Q.
Which of the transitions in hydrogen atom emits a photon of lowest frequency (n = quantum number)
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a
n = 2 to n = 1
b
n = 4 to n = 3
c
n = 3 to n = 1
d
n = 4 to n = 2
answer is B.
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Detailed Solution
From diagramE1=−13.6−(−3.4)=−10.2eVE2=−13.6−(−1.51)=−12.09eVE3=−1.51−(−0.85)=−0.66eVE4=−3.4−(−1.51)=−1.89eVE3 is least i.e. frequency is lowest.
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