Q.

Which of the transitions in hydrogen atom emits a photon of lowest frequency  (n = quantum number)

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a

n = 2 to n = 1

b

n = 4 to n = 3

c

n = 3 to n = 1

d

n = 4 to n = 2

answer is B.

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Detailed Solution

From diagramE1=−13.6−(−3.4)=−10.2eVE2=−13.6−(−1.51)=−12.09eVE3=−1.51−(−0.85)=−0.66eVE4=−3.4−(−1.51)=−1.89eVE3 is least i.e. frequency is lowest.
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