While boiling 1 gm of water at pressure 1.013×105 N/m3, its volume 1471 cm3 from 1 cm3, then work done by the system is
148.911 J
150 J
130.24 J
120.57 J
dQ=dU+dW=dU+pdvdW=pdv=1.013×105×(1470)×10−6=148.91 joule