First slide

First law of thermodynamics

Question

While boiling 1 gm of water at pressure 1.013×10⁵ N/m³, its volume 1471 cm³ from 1 cm³, then work done by the system is

Easy

A

148.911 J
B

150 J
C

130.24 J
D

120.57 J

Solution

$\begin{array}{l} dQ = dU + dW = dU + pdv \\ dW = pdv = 1 .013 \times 10^{5} \times (1470) \times 10^{- 6} \\ = 148 .91 joule \end{array}$

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