While a particle executes simple harmonic motion, the rate of change of acceleration is maximum and minimum, respectively at
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a
the mean position and extreme positions
b
the extreme positions and mean position
c
the mean position alternatively
d
the extreme positions alternatively
answer is A.
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Detailed Solution
a=-ω2x =ω2x (numerically) Rate of change of acceleration.dadt=ω2dxdt=ω2v =ω3A2-x2For da/dt to be maximum, x2 should be minimum i.e., x = 0 and For da/dt to be minimum x2 should be maximum i.e., x = ± a.