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Questions  

A whistle giving out 450Hz approaches a stationary observer at a speed of 33m/sec . The frequency heard by the observer in Hz  is  given velocity of sound=330 ms-1

a
409
b
429
c
517
d
500

detailed solution

Correct option is D

VS=33 m/sec →VS                            O Source                    observer                                    V0=0 ⇒n1=nV−V0V−VS =450VV−33 =450330330−33 =500 Hz

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