First slide

Doppler's effect

Question

A whistle giving out $450 H z$ approaches a stationary observer at a speed of $33 m / \sec$ . The frequency heard by the observer in $H z$ is given velocity of sound=330 $m s^{- 1}$

Moderate

A

409
B

429
C

517
D

500

Solution

$V_{S} = 33 m / \sec \underset{V S}{\to} O S o u r c e o b s e r v e r V_{0} = 0 \Rightarrow n^{1} = n [\frac{V - V_{0}}{V - V_{S}}] = 450 [\frac{V}{V - 33}] = 450 [\frac{330}{330 - 33}] = 500 H z$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App