First slide

Doppler

Question

A whistle giving out 450 Hz approaches a stationary observer at a speed of 33 m/s. The frequency heard by the observer in Hz is

Moderate

A

409
B

429
C

517
D

500

Solution

The apparent frequency heard by the observer is given by
$n^{'} = \frac{v}{v - v_{S}} n = \frac{330}{330 - 33} \times 450 = \frac{330}{297} \times 450 = 500 Hz$

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