A whistle sends out 256 waves in a second. If the whistle approaches the observer with velocity 1/3 of the velocity of sound in air, the number of waves per second the observer will receive
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a
384
b
192
c
300
d
200
answer is A.
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Detailed Solution
Wave number = 1λ but 1λ'=1λvv−vs and vs=v3∴ (W.N.)’ = (W.N.) vv−v/3=256×v2v/3=32×256=384