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Q.

The width of a river is 80 m . The velocity of a boat in still water is 10 m/s .  If water flows in the river with a velocity of 6 m/s , the difference in times taken to cross the river in the shortest path and the shortest time is

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a

1 s

b

10 s

c

32s

d

2s

answer is D.

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Detailed Solution

In shortest path t=dvb2−vr2=808=10 s In shortest time t=dvb=808=10 s The difference is 2s .
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