The width of a river is 80 m . The velocity of a boat in still water is 10 m/s . If water flows in the river with a velocity of 6 m/s , the difference in times taken to cross the river in the shortest path and the shortest time is

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1 s

10 s

32s

answer is D.

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Detailed Solution

In shortest path t=dvb2−vr2=808=10 s In shortest time t=dvb=808=10 s The difference is 2s .

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