Q.

A wind with speed 40 m/s blows parallel to the roof of a house. The area of the roof is 250 m2. Assuming that the pressure inside the house is atmospheric pressure, the force exerted by the wind on the roof and the direction of the force will be (ρair= 1.2 kg/m3)

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a

4.8 × 10 5N, downwards

b

4.8 × 105 N, upwards

c

2.4 × 105 N, upwards

d

2.4 × 105 N, downwards

answer is C.

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Detailed Solution

Applying Bernoulli's theorem just above and just below the roof,     P+12ρv2 = P0+0     (Po-P) = 12ρv2 = ∆PHence lift of the roofF = ∆P.A = 12ρAv2 = 12×1.2×(40)2×250 = 2.4 × 105N
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A wind with speed 40 m/s blows parallel to the roof of a house. The area of the roof is 250 m2. Assuming that the pressure inside the house is atmospheric pressure, the force exerted by the wind on the roof and the direction of the force will be (ρair= 1.2 kg/m3)