A wire is bent in the form of a quadrant of circle of radius 'a' as shown in the Fig. 8.93. The magnetic field at centre O due to current i is :

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μ04π.2πia

μ04π.πia

μ04π.πi2a

zero

answer is C.

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Detailed Solution

Magnetic field due to a circular ring at center= μoi2amagnetic field due to quadrant= 14μoi2a

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