A wire A, bent in the shape of an arc of a circle, carrying a current of 2 A and having radius 2 cm and another wire B, also bent in the shape of arc of a circle, carrying a current of 3 A and having radius of 4 cm, are placed as shown in the figure. The ratio of the magnetic fields due to the wires A and B at the common centre O is :
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a
6 : 5
b
4 : 6
c
6 : 4
d
2 : 5
answer is A.
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Detailed Solution
Magnetic field due to arc of circular current =θ360° μ0i2R at the center. Here required ratio =BABB=θA iA/RAθB iB/RB=270300×23×42=65