First slide

Elastic behaviour of solids

Question

A wire can sustain the weight of 20 kg before breaking. If the wire is cut into two equal parts, each part can sustain a weight of

Moderate

A

10 kg
B

20 kg
C

40 kg
D

35 kg

Solution

The maximum load which a wire can sustain is a property of the material of wire and it depends on the cross-sectional area. $σ_{breaking}$ is a characteristic property of material of wire and is independent of length or breadth (dimensions) of the wire. $\frac{W_{1}}{A_{1}} = \frac{W_{2}}{A_{2}}$
The maximum load that can sustain is independent of length of the wire.

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App