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A wire carrying current I is bent in the shape ABCDEFA as shown, where rectangle ABCDA and ADEFA are perpendicular to each other. If the sides of the rectangles are of lengths a and b, then the magnitude and direction of magnetic moment of the loop ABCDEFA is:

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a

2abI, along j^2+k^2

b

abI, along j^5+2k^5

c

abI, along j^2+k^2

d

2abI, along j^5+2k^5

answer is A.

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Detailed Solution

Magnetic moment of loop ABCDAM1¯=Iab k^Magnetic moment of loop ADEFA M2¯=Iab j^Net magnetic moment Mnet¯=M1¯+M2¯ Mnet¯=Iab j^+k^ Mnet¯=2IabUnit vector along magnetic moment direction= j^+k^2

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A wire carrying current I is bent in the shape ABCDEFA as shown, where rectangle ABCDA and ADEFA are perpendicular to each other. If the sides of the rectangles are of lengths a and b, then the magnitude and direction of magnetic moment of the loop ABCDEFA is: