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Q.

A wire of a certain material is stretched slowly by ten percent. Its new resistance and specific resistance become respectively

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a

1.2 times, 1.1 times

b

1.2 L times, same

c

both remain the same

d

1.1 times, 1.1 times

answer is B.

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Detailed Solution

Specific resistance ρ will remain same as it is the intrinsic property of material.Original resistance of the wire, R= ρlAor    R= lA   or  R ∝  l2V     as  V= Aland  R'  ∝  l+10% l2VTherefore,   R'R=  l+10100  l2l2or    R'R=  11l210l2 =  121100or     R'  =1.21  R
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