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A wire of a certain material is stretched slowly by ten percent. Its new resistance and specific resistance become respectively

a
1.2 times, 1.1 times
b
1.2 L times, same
c
both remain the same
d
1.1 times, 1.1 times

detailed solution

Correct option is B

Specific resistance ρ will remain same as it is the intrinsic property of material.Original resistance of the wire, R= ρlAor    R= lA   or  R ∝  l2V     as  V= Aland  R'  ∝  l+10% l2VTherefore,   R'R=  l+10100  l2l2or    R'R=  11l210l2 =  121100or     R'  =1.21  R

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