A wire of a certain material is stretched slowly by ten percent. Its new resistance and specific resistance become respectively
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
1.2 times, 1.1 times
b
1.2 L times, same
c
both remain the same
d
1.1 times, 1.1 times
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Specific resistance ρ will remain same as it is the intrinsic property of material.Original resistance of the wire, R= ρlAor R= lA or R ∝ l2V as V= Aland R' ∝ l+10% l2VTherefore, R'R= l+10100 l2l2or R'R= 11l210l2 = 121100or R' =1.21 R