A wire of cross section A is stretched horizontally between two clamps located 2l m apart. A weight W kg is suspended from the mid-point of the wire. If the mid-point sags vertically through a distance x < 1 the strain produced is
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a
2x2l2
b
x2l2
c
x22l2
d
None of these
answer is C.
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Detailed Solution
Here change in length isΔl=(AC+BC)−2l=2l2+x21/2−2l=2l1+x2l21/2−2l=2l1+12x2l2−2l=x2l∴ Strain =Δl2l=x22l2