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# A wire of cross sectional area $4m{m}^{2}$  is fixed between two points at  ${30}^{0}C$.  $Y=2×{10}^{11}Pa$ and  $\alpha ={10}^{-5}{/}^{0}C$ when the temperature falls to ${20}^{0}C$ then tension in the string is

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a
600N
b
60N
c
80N
d
800N
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detailed solution

Correct option is C

Force in the wire due to change in temperature is F=YAαΔt here Y is youngs modulus=2x1011N/m2; A is cross section area =4sq.mm;  α is coefficient of linear expansion=10-5/C  0 ; Δt is change in temperature =30-20=100C; substitute the given values in above equation F=2×1011×4×10−6×10−5×10 F=80N=tension in the wire

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On loading a metal wire of cross section  ${10}^{-6}{m}^{2}$  and length 2m by a mass of 210 kg it extends by 16mm and suddenly broke from the point of support. If density of that metal is $8000kg{m}^{-3}$  and its specific heat is $420Jk{g}^{-1}{K}^{-1}$  the rise in temperature of wire is $\left(g=10m{s}^{-2}\right)$

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