A wire of cross sectional area $$4mm2$$ is fixed between two points at $$300C$$. $$Y=2$$×$$1011Pa$$ and α$$=10$$−$$5/0C$$ when the temperature falls to $$200C$$ then tension in the string is

Question

A wire of cross sectional area $$4mm2$$  is fixed between two points at  $$300C$$.  $$Y=2$$×$$1011Pa$$ and  α$$=10$$−$$5/0C$$ when the temperature falls to $$200C$$ then tension in the string is

Infinity Learn · Accepted Answer

Force in the wire due to change in temperature is $$F=YA$$αΔt here Y is youngs $$modulus=2x1011N/m2$$; A is cross section area $$=4sq$$.mm;  α is coefficient of linear $$expansion=10-5/C$$  $$0$$ ; Δt is change in temperature $$=30-20=100C$$; substitute the given values in above equation $$F=2$$×$$1011$$×$$4$$×$$10$$−$$6$$×$$10$$−$$5$$×$$10$$ $$F=80N=tension$$ in the wire

A wire of cross sectional area $4 m m^{2}$ is fixed between two points at $30^{0} C$ . $Y = 2 \times 10^{11} P a$ and $α = 10^{- 5} /^{0} C$ when the temperature falls to $20^{0} C$ then tension in the string is

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A wire of cross sectional area 4mm2 is fixed between two points at 300C. Y=2×1011Pa and α=10−5/0C when the temperature falls to 200C then tension in the string is

Unlock the full solution & master the concept.

Ready to Test Your Skills?

free study material

A wire of cross sectional area $4 m m^{2}$ is fixed between two points at $30^{0} C$ . $Y = 2 \times 10^{11} P a$ and $α = 10^{- 5} /^{0} C$ when the temperature falls to $20^{0} C$ then tension in the string is