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A wire of cross sectional area 4mm2  is fixed between two points at  300C.  Y=2×1011Pa and  α=105/0C when the temperature falls to 200C then tension in the string is

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By Expert Faculty of Sri Chaitanya
a
600N
b
60N
c
80N
d
800N
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detailed solution

Correct option is C

Force in the wire due to change in temperature is F=YAαΔt here Y is youngs modulus=2x1011N/m2; A is cross section area =4sq.mm;  α is coefficient of linear expansion=10-5/C  0 ; Δt is change in temperature =30-20=100C; substitute the given values in above equation F=2×1011×4×10−6×10−5×10 F=80N=tension in the wire


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