Q.

A wire of cross sectional area 4mm2 is fixed between two points at 300C. Y=2×1011Pa and α=10−5/0C when the temperature falls to 200C then tension in the string is

Moderate

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600N

60N

80N

800N

answer is 3.

(Detailed Solution Below)

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Detailed Solution

Force in the wire due to change in temperature is F=YAαΔt here Y is youngs modulus=2x1011N/m2; A is cross section area =4sq.mm; α is coefficient of linear expansion=10-5/C 0 ; Δt is change in temperature =30-20=100C; substitute the given values in above equation F=2×1011×4×10−6×10−5×10 F=80N=tension in the wire

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