Q.

A wire of cross sectional area 4mm2  is fixed between two points at  300C.  Y=2×1011Pa and  α=10−5/0C when the temperature falls to 200C then tension in the string is

Moderate

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a

600N

b

60N

c

80N

d

800N

answer is 3.

(Detailed Solution Below)

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Detailed Solution

Force in the wire due to change in temperature is F=YAαΔt here Y is youngs modulus=2x1011N/m2; A is cross section area =4sq.mm;  α is coefficient of linear expansion=10-5/C  0 ; Δt is change in temperature =30-20=100C; substitute the given values in above equation F=2×1011×4×10−6×10−5×10 F=80N=tension in the wire
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