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A wire of cross sectional area $4 m m^{2}$ is fixed between two points at $30^{0} C$ . $Y = 2 \times 10^{11} P a$ and $α = 10^{- 5} /^{0} C$ when the temperature falls to $20^{0} C$ then tension in the string is

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a

600N

b

60N

c

80N

d

800N

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detailed solution

Correct option is C

Force in the wire due to change in temperature is F=YAαΔt here Y is youngs modulus=2x1011N/m2; A is cross section area =4sq.mm; α is coefficient of linear expansion=10-5/C 0 ; Δt is change in temperature =30-20=100C; substitute the given values in above equation F=2×1011×4×10−6×10−5×10 F=80N=tension in the wire

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