A wire of cross-section A is stretched horizontally between two clamps located 2l metre apart. A weight W kg is suspended from the mid point of the wire. If the mid pint sags vertically through a distance x < I the strain produced is:
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a
2x2l2
b
x2l2
c
x22l2
d
None of these
answer is C.
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Detailed Solution
Here change in length is ∆l = [AC + BC]-2l = 2(l+x2)12-2l= 2l(1+x2l2)12-2l = 2l(1+12x2l2)-2l = x2l∴ Strain = ∆l2l = x22l2Correct choice is (3).