Download the app

Questions  

A wire of cross-sectional area A forms three sides of a square and is free to rotate about axis OO1. If the structure is deflected by an angle θ from the vertical when current I is passed through it in a magnetic field B acting vertically upward and density of the wire is ρ, then the value of θ is given by

a
2AρgiB=cotθ
b
2AρgiB=tanθ
c
AρgiB=sinθ
d
Aρg2iB=cosθ

detailed solution

Correct option is A

Let a is the side of square. Torque of current =MBsin(90-θ) =MBcosθ=ia2Bcosθ  Mass of each side =m=ρAa  Torque of gravity =2mga2sinθ+mgasinθ =2mgasinθ=2ρAga2sinθ Now, both torques should be same  i.e.,   ia2Bcosθ=2ρAga2sinθ ⇒  cotθ=2ρAgiB

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

If 10% of the current passes through a moving coil galvanometer of resistance 99 ohm, then the shunt resistance will be:


phone icon
whats app icon