A wire of cross-sectional area A forms three sides of a square and is free to rotate about axis OO1. If the structure is deflected by an angle θ from the vertical when current I is passed through it in a magnetic field B acting vertically upward and density of the wire is ρ, then the value of θ is given by
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
2AρgiB=cotθ
b
2AρgiB=tanθ
c
AρgiB=sinθ
d
Aρg2iB=cosθ
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Let a is the side of square. Torque of current =MBsin(90-θ) =MBcosθ=ia2Bcosθ Mass of each side =m=ρAa Torque of gravity =2mga2sinθ+mgasinθ =2mgasinθ=2ρAga2sinθ Now, both torques should be same i.e., ia2Bcosθ=2ρAga2sinθ ⇒ cotθ=2ρAgiB