Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A wire of cross-sectional area A forms three sides of a square and is free to rotate about axis OO1 . If the structure is deflected by an angle θ from the vertical when current  i is passed through it in a magnetic field B acting vertically upwards and density of the wire is ρ , then the value of θ is given by

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

2AρgiB=cotθ

b

2AρgiB=tanθ

c

AρgiB=sinθ

d

Aρg2iB=cosθ

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

Let  a is the side of square.Torque of current =   MB=sin(90−θ)=MBcosθ=ia2BcosθMass of each side=  m=ρAaTorque of gravity =  2mga2sinθ+mg a sinθ =2mg a sinθ=2ρAga2sinθNow, at equilibrium both torques should be samei.e.,  ia2Bcosθ=2ρAga2sinθ⇒ cotθ=2ρAgiB .
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon