A wire of fixed length is wound in such a way that it forms a solenoid of length 'l' and radius 'r'. Its self-inductance is found to be Z. Now if same wire is wound in such a way that it forms a solenoid of length I /2 and radius r /2, then the self-inductance will be
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a
2L
b
L
c
4L
d
8L
answer is A.
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Detailed Solution
L=μ0N2πr2l Length of wire =N2πr= Constant (=C, suppose )∴ L=μ0C2πr2πr2l∴ L∝1l∴ Self-inductance will become 2L .