A wire has mass 0.3±0.003 g , radius 0.5±0.005 mm and length 6±0.06 cm . The maximum percentage error in the measurement of its density is
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a
2
b
3
c
4
d
5
answer is C.
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Detailed Solution
density=massvolume=masscross section area×lengthρ=mV=mπr2l∆ρρ=∆mm+2∆rr+∆ll =0.0030.3+20.00050.05+0.066 = 3300+25500+6600 =4100Percentage error in density is ∆ρρ×100=4%