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Q.

A wire having area of cross section 10−6m2 is stretched to increase its length by 0.1%. Then tension produced is 1000N. Then elastic potential energy stored per unit volume of the wire is

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a

5×105J/m3

b

108J/m3

c

2×106J/m3

d

5×106J/m3

answer is A.

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Detailed Solution

Y=StressStrain=103/10−60.1×10−2N/m2∴u=12Ye2=12×1012×J/m3=5×105J/m3
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