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A wire having a linear density of  0.05g/cm is stretched between two rigid supports with a tension of 4.5×102N it is observed that the wire resonance at a frequency of 420 Hz. The next higher frequency at which the wire resonates is 490 Hz. Determine the length of the wire.

a
2.14 m
b
3.2 m
c
4 m
d
8 m

detailed solution

Correct option is A

Expression for Frequency when both ends are tied f = n2LTμ  Now,  420=n2LTμ→(i) 490=n+12LTμ→(ii) Divide equation    i÷iin=6Putting in equation (i)420=62L4.5×1020.05×10−310−2⇒ L=2.14 m

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Similar Questions

A wire having a linear density of 5 g/m is stretched between two rigid supports with a tension of 450 N. It is observed that the wire resonates at a frequency of 420 Hz. The next highest frequency at which the same wire resonates is 490 Hz. Find the length of the wire. (in m)


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