A wire having a linear density of 0.10kg/m is kept under a tension of 490N. It is observed that it resonates at a frequency of 400Hz and the next higher frequency is 450Hz. The length of the wire is

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14m

0.7m

1.6 m

0.49 m

answer is B.

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Detailed Solution

n2lTμ = 400 −−−−(1)andn+12lTμ = 450 −−−−(2) ∴ n+1n = 450400 ⇒ n= 8 From−(1) 82l×4900.1 = 400 ⇒ l= 0.7m

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