A wire of 9.8×10−3 kgm−1 passes over a frictionless light pulley fixed on the top of a frictionless inclined plane which makes an angle of 30° with the horizontal. Masses m and M are tied at the two ends of wire such that m rests on the plane and M hangs freely vertically downwards. The entire system is in equilibrium and a transverse wave propagates along the wire with a velocity of 100 ms–1. Choose the correct option

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m = 20 kg

m = 5 kg

m = 2 kg

m = 7 kg

answer is A.

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Detailed Solution

For equilibrium Mg=mg sin30=T⇒M=m2v=Tμ⇒100=Mg9.8×10−3=M(9.8)9.8×10−3⇒100=M(1000) ⇒M=10 kg and m=20 kg

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